The Minnesota Timberwolves don’t need the first overall pick in this year’s draft.
As it stands, the Minnesota Timberwolves have a 5.3 percent chance to win the number one overall pick in Tuesday’s lottery.
Minnesota has only picked first overall one time in their franchise’s history. That came very recently in 2015 when they selected Karl-Anthony Towns.
Remember, Andrew Wiggins, also a former number one overall pick was selected by the Cleveland Cavaliers and later traded to Minnesota.
After two seasons, Towns has surpassed expectations and continues to blossom, not only into one of the league’s best big men but one of the league’s best players overall. He looks to be on the verge of being a savior for a franchise who desperately needed one since Kevin Garnett left.
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Most fans hope that Minnesota can strike lottery gold and land the number one pick. Heck, fans would even take the second or third pick given the talent at the top of this year’s draft.
They are dreaming of a Lonzo Ball- Towns pairing and how unstoppable that may be on offense.
My question to you is, what if those fans are wrong?
What if the Minnesota Timberwolves are actually better off not landing the first pick in June’s draft?
Based on a plethora of factors, it may be better off for the Wolves if they do not end up winning Tuesday’s lottery.
The best thing for their franchise may be to stay put at their projected sixth spot in the draft.
Let’s play some Devil’s Advocate and take a look at the other side of the argument.
Here are five reasons why the Minnesota Timberwolves don’t need the first pick in the draft.